colossus wrote:
1) What is the reason for the 1.5k resistor in series with the 10k/100k pot? I'm assuming to always have a resistance of 1.5 k min there between 1 and 2...but why? And why that value?
2) What is the necessity of the mixing diode or resistor? I tried two oscillators from the 40106 w/o any mixing resistors and the sound barely changed much. And why that value resistor?
3) Why is C5 there at all?
4) In general, what is the basis for deciding on particular pot values in a circuit like this? I get why between 1 and 2 on the 40106 -- i.e., frequency, but why say 100k for volume over 50k?
5) FINALLY, why are there no decoupling caps here?
Phew...that's a lot of questions.
1) You're correct. It keeps a minimum of resistance there, presumably to keep you in the range of human hearing.
2) When you're mixing multiple signals those resistors kind of prevent the electricity from backing up into your pots, and escaping out some other line. It keeps things separated. I've never used the diode method, but it looks like an even better promise of "electricity only going one way."
3) To block the DC voltage from your other gear. Of course, most of your other gear will have input caps that block DC voltage as well, but if you're mixing with a guitar or something you're going to need that.
4) Volume pots have a little to do with the high frequency response (higher value = more treble) and some to do with an intuitive rotation to volume change ratio. I'm pretty much an A100k guy.
5) You mean, like between power and ground? Not needed. I've made a million and a half circuits using these hex inverters with no decoupling caps with no trouble.
ENJOY THE SQAUREWAVES!